1050=16t^2

Solution for 1050=16t^2 equation:

1050=16t^2

We move all terms to the left:

1050-(16t^2)=0

a = -16; b = 0; c = +1050;
Δ = b2-4ac
Δ = 02-4·(-16)·1050
Δ = 67200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{67200}=\sqrt{1600*42}=\sqrt{1600}*\sqrt{42}=40\sqrt{42}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{42}}{2*-16}=\frac{0-40\sqrt{42}}{-32}
=-\frac{40\sqrt{42}}{-32}
=-\frac{5\sqrt{42}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{42}}{2*-16}=\frac{0+40\sqrt{42}}{-32}
=\frac{40\sqrt{42}}{-32}
=\frac{5\sqrt{42}}{-4}
$